Transpose a Matrix

easynumpy_basics

Implement transpose_2d(X).

Given a 2D array X of shape (m, n), return its transpose of shape (n, m): the element at position (j, i) of the result equals X[i, j]. No for/while loops.

Constraints

no for/while loops

Your solution

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Hints

Hint 1

X.T (or np.transpose(X)) swaps the two axes of a 2D array.